django ajax post data view.py (1) 썸네일형 리스트형 django ajax post data and view.py ajax (javascirpt) var SendInfo= [];var data = { date:$("#datetimepicker").val(), time:$("#time").val(), people:$("#people").val()}SendInfo.push(data); $.ajax({ url: YOUR_URL, dataType: "json", data: JSON.stringify(SendInfo), type: 'POST', success: function(data){ console.log(data.data) }}); view.py data = json.loads(request.body)print data[0]["date"]print data[0]["time"]print data[0]["people"] 이전 1 다음